• Re: The halting problem is self-contradictory

    From olcott@polcott333@gmail.com to comp.theory on Sun Oct 19 11:08:34 2025
    From Newsgroup: comp.theory

    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:


    Before you can understand any of this you must
    first understand the semantic halting property
    of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is
    that DD halts.

    Although finite strings do encode that not
    all finite string *INPUTS* encode that.

    No sense diving into the middle of things until
    after you first have this mandatory prerequisite.

    An error in the middle of things is an error.


    No it is a lack of comprehension of the correct basis.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From joes@noreply@example.org to comp.theory on Sun Oct 19 18:43:48 2025
    From Newsgroup: comp.theory

    Am Sun, 19 Oct 2025 11:08:34 -0500 schrieb olcott:
    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:

    Before you can understand any of this you must first understand the
    semantic halting property of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is that DD
    halts.

    Although finite strings do encode that not all finite string *INPUTS*
    encode that.

    The encoding of DD specifies a call to the terminating HHH.
    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Mikko@mikko.levanto@iki.fi to comp.theory on Mon Oct 20 12:22:28 2025
    From Newsgroup: comp.theory

    On 2025-10-19 16:08:34 +0000, olcott said:

    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:


    Before you can understand any of this you must
    first understand the semantic halting property
    of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is
    that DD halts.

    Although finite strings do encode that not
    all finite string *INPUTS* encode that.

    No sense diving into the middle of things until
    after you first have this mandatory prerequisite.

    An error in the middle of things is an error.

    No it is a lack of comprehension of the correct basis.

    Not necessarily. There are other possibilities to err in the middle
    of things. But you are totally wrong as your lack of comprenesion
    indeed contributes to a large part of your errors.
    --
    Mikko

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  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 10:24:59 2025
    From Newsgroup: comp.theory

    On 10/19/2025 1:43 PM, joes wrote:
    Am Sun, 19 Oct 2025 11:08:34 -0500 schrieb olcott:
    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:

    Before you can understand any of this you must first understand the
    semantic halting property of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is that DD
    halts.

    Although finite strings do encode that not all finite string *INPUTS*
    encode that.

    The encoding of DD specifies a call to the terminating HHH.


    The is not the HHH that the simulated DD() calls.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 12:06:16 2025
    From Newsgroup: comp.theory

    On 10/20/2025 4:22 AM, Mikko wrote:
    On 2025-10-19 16:08:34 +0000, olcott said:

    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:


    Before you can understand any of this you must
    first understand the semantic halting property
    of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is
    that DD halts.

    Although finite strings do encode that not
    all finite string *INPUTS* encode that.

    No sense diving into the middle of things until
    after you first have this mandatory prerequisite.

    An error in the middle of things is an error.

    No it is a lack of comprehension of the correct basis.

    Not necessarily. There are other possibilities to err in the middle
    of things. But you are totally wrong as your lack of comprenesion
    indeed contributes to a large part of your errors.


    <Input to LLM systems>
    Please think this all the way through without making any guesses

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
    possibly reach its own simulated final halt state then:
    abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }

    int main()
    {
    HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    The above is the correct basis that conclusively proves
    that the input to HHH(DD) specifies non-halting behavior
    that is correct rejected.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From joes@noreply@example.org to comp.theory on Mon Oct 20 17:18:15 2025
    From Newsgroup: comp.theory

    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:
    Am Sun, 19 Oct 2025 11:08:34 -0500 schrieb olcott:
    On 10/19/2025 3:42 AM, Mikko wrote:

    The only semantic property relevant to the halting problem is that DD
    halts.
    Although finite strings do encode that not all finite string *INPUTS*
    encode that.
    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.
    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 12:34:16 2025
    From Newsgroup: comp.theory

    On 10/20/2025 12:18 PM, joes wrote:
    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:
    Am Sun, 19 Oct 2025 11:08:34 -0500 schrieb olcott:
    On 10/19/2025 3:42 AM, Mikko wrote:

    The only semantic property relevant to the halting problem is that DD >>>>> halts.
    Although finite strings do encode that not all finite string *INPUTS*
    encode that.
    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.


    You ignore important details.

    <Input to LLM systems>
    Please think this all the way through without making any guesses

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
    possibly reach its own simulated final halt state then:
    abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }

    int main()
    {
    HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    The above is the correct basis that conclusively proves
    that the input to HHH(DD) specifies non-halting behavior
    that is correctly rejected.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From joes@noreply@example.org to comp.theory on Mon Oct 20 17:41:09 2025
    From Newsgroup: comp.theory

    Am Mon, 20 Oct 2025 12:34:16 -0500 schrieb olcott:
    On 10/20/2025 12:18 PM, joes wrote:
    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:

    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.
    You ignore important details.
    What details? Every DD calls HHH, and every HHH aborts.
    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 12:47:36 2025
    From Newsgroup: comp.theory

    On 10/20/2025 12:41 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:34:16 -0500 schrieb olcott:
    On 10/20/2025 12:18 PM, joes wrote:
    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:

    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.
    You ignore important details.
    What details? Every DD calls HHH, and every HHH aborts.


    The semantic halting property of the input finite
    string overrules everything else because Turing machines
    only compute their mapping from input finite strings.

    <Input to LLM systems>
    Simulating Termination Analyzer HHH correctly simulates its input until:
    (a) It correctly detects that its simulated input cannot
    possibly reach its own simulated final halt state then:
    abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From joes@noreply@example.org to comp.theory on Mon Oct 20 18:09:04 2025
    From Newsgroup: comp.theory

    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:34:16 -0500 schrieb olcott:
    On 10/20/2025 12:18 PM, joes wrote:
    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:

    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.
    You ignore important details.
    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules
    everything else because Turing machines only compute their mapping from
    input finite strings.
    The input contains an encoding of the abort.
    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 13:42:56 2025
    From Newsgroup: comp.theory

    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:34:16 -0500 schrieb olcott:
    On 10/20/2025 12:18 PM, joes wrote:
    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:

    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.
    You ignore important details.
    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules
    everything else because Turing machines only compute their mapping from
    input finite strings.
    The input contains an encoding of the abort.


    If (a) is met (and it is met) then the input specifies non halting
    behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all
    programs halt.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From joes@noreply@example.org to comp.theory on Mon Oct 20 19:21:33 2025
    From Newsgroup: comp.theory

    Am Mon, 20 Oct 2025 13:42:56 -0500 schrieb olcott:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:

    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules
    everything else because Turing machines only compute their mapping
    from input finite strings.
    The input contains an encoding of the abort.
    If (a) is met (and it is met) then the input specifies non halting
    behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all programs halt.
    It is not met. Whether an input halts does not depend on what HHH says.
    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 14:30:16 2025
    From Newsgroup: comp.theory

    On 10/20/2025 2:21 PM, joes wrote:
    Am Mon, 20 Oct 2025 13:42:56 -0500 schrieb olcott:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:

    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules
    everything else because Turing machines only compute their mapping
    from input finite strings.
    The input contains an encoding of the abort.
    If (a) is met (and it is met) then the input specifies non halting
    behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all programs
    halt.
    It is not met. Whether an input halts does not depend on what HHH says.


    Whether the directly executed DD() halts or
    not *does depend on what HHH(DD) says* if
    HHH(DD) says 1, then DD() gets stuck in a loop.

    It is only the actual behavior of the actual
    input that is within the scope of any Turing
    machine based decider.

    int sum(int x, int y) { return x + y; }
    if it is required that sum(3,4) return
    the sum of 5 + 6 then this requirement is wrong.

    If it is required that HHH(DD) report on anything
    besides the actual behavior that its actual
    input actually specifies then this requirement
    is wrong.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Kaz Kylheku@643-408-1753@kylheku.com to comp.theory on Mon Oct 20 20:59:31 2025
    From Newsgroup: comp.theory

    On 2025-10-20, olcott <polcott333@gmail.com> wrote:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:34:16 -0500 schrieb olcott:
    On 10/20/2025 12:18 PM, joes wrote:
    Am Mon, 20 Oct 2025 10:24:59 -0500 schrieb olcott:
    On 10/19/2025 1:43 PM, joes wrote:

    The encoding of DD specifies a call to the terminating HHH.
    The is not the HHH that the simulated DD() calls.
    It has the same code.
    You ignore important details.
    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules
    everything else because Turing machines only compute their mapping from
    input finite strings.
    The input contains an encoding of the abort.


    If (a) is met (and it is met) then the input specifies non halting

    It is not met for the diagonal case like HHH(DD). It is met for
    non-diagonal cases like HHH(Infinite_Loop).
    --
    TXR Programming Language: http://nongnu.org/txr
    Cygnal: Cygwin Native Application Library: http://kylheku.com/cygnal
    Mastodon: @Kazinator@mstdn.ca
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From joes@noreply@example.org to comp.theory on Mon Oct 20 22:15:26 2025
    From Newsgroup: comp.theory

    Am Mon, 20 Oct 2025 14:30:16 -0500 schrieb olcott:
    On 10/20/2025 2:21 PM, joes wrote:
    Am Mon, 20 Oct 2025 13:42:56 -0500 schrieb olcott:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:

    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules
    everything else because Turing machines only compute their mapping
    from input finite strings.
    The input contains an encoding of the abort.
    If (a) is met (and it is met) then the input specifies non halting
    behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all
    programs halt.
    It is not met. Whether an input halts does not depend on what HHH says.
    Whether the directly executed DD() halts or not *does depend on what
    HHH(DD) says* if HHH(DD) says 1, then DD() gets stuck in a loop.
    That’s not the input.
    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 17:33:33 2025
    From Newsgroup: comp.theory

    On 10/20/2025 5:15 PM, joes wrote:
    Am Mon, 20 Oct 2025 14:30:16 -0500 schrieb olcott:
    On 10/20/2025 2:21 PM, joes wrote:
    Am Mon, 20 Oct 2025 13:42:56 -0500 schrieb olcott:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:

    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules >>>>>> everything else because Turing machines only compute their mapping >>>>>> from input finite strings.
    The input contains an encoding of the abort.
    If (a) is met (and it is met) then the input specifies non halting
    behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all
    programs halt.
    It is not met. Whether an input halts does not depend on what HHH says.
    Whether the directly executed DD() halts or not *does depend on what
    HHH(DD) says* if HHH(DD) says 1, then DD() gets stuck in a loop.
    That’s not the input.


    <Input to LLM systems>

    Perform the complete simulation specified in main() and provide a
    full execution trace before doing anything else.

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
    possibly reach its own simulated final halt state then:
    abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.

    (c) Neither (a) nor (b) is correct return -1

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }

    int main()
    {
    HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    I adapted the above to conform to what Kaz said
    to give it an escape hatch.

    Just the updated three-way halts does_not_halt neither. https://claude.ai/share/8c4a4fdc-5faf-4525-8c08-e133d258da88
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 17:43:16 2025
    From Newsgroup: comp.theory

    On 10/20/2025 5:33 PM, olcott wrote:
    On 10/20/2025 5:15 PM, joes wrote:
    Am Mon, 20 Oct 2025 14:30:16 -0500 schrieb olcott:
    On 10/20/2025 2:21 PM, joes wrote:
    Am Mon, 20 Oct 2025 13:42:56 -0500 schrieb olcott:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:

    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules >>>>>>> everything else because Turing machines only compute their mapping >>>>>>> from input finite strings.
    The input contains an encoding of the abort.
    If (a) is met (and it is met) then the input specifies non halting
    behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all
    programs halt.
    It is not met. Whether an input halts does not depend on what HHH says. >>> Whether the directly executed DD() halts or not *does depend on what
    HHH(DD) says* if HHH(DD) says 1, then DD() gets stuck in a loop.
    That’s not the input.


    <Input to LLM systems>

    Perform the complete simulation specified in main() and provide a
    full execution trace before doing anything else.

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
       possibly reach its own simulated final halt state then:
       abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.

    (c) Neither (a) nor (b) is correct return -1

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
      int Halt_Status = HHH(DD);
      if (Halt_Status)
        HERE: goto HERE;
      return Halt_Status;
    }

    int main()
    {
      HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    I adapted the above to conform to what Kaz said
    to give it an escape hatch.

    Just the updated three-way halts does_not_halt neither. https://claude.ai/share/8c4a4fdc-5faf-4525-8c08-e133d258da88


    Grok, Gemini and ChatGPT 5.0 all agree.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Chris M. Thomasson@chris.m.thomasson.1@gmail.com to comp.theory on Mon Oct 20 15:59:32 2025
    From Newsgroup: comp.theory

    On 10/20/2025 3:43 PM, olcott wrote:
    On 10/20/2025 5:33 PM, olcott wrote:
    On 10/20/2025 5:15 PM, joes wrote:
    Am Mon, 20 Oct 2025 14:30:16 -0500 schrieb olcott:
    On 10/20/2025 2:21 PM, joes wrote:
    Am Mon, 20 Oct 2025 13:42:56 -0500 schrieb olcott:
    On 10/20/2025 1:09 PM, joes wrote:
    Am Mon, 20 Oct 2025 12:47:36 -0500 schrieb olcott:
    On 10/20/2025 12:41 PM, joes wrote:

    What details? Every DD calls HHH, and every HHH aborts.
    The semantic halting property of the input finite string overrules >>>>>>>> everything else because Turing machines only compute their mapping >>>>>>>> from input finite strings.
    The input contains an encoding of the abort.
    If (a) is met (and it is met) then the input specifies non halting >>>>>> behavior. Non-halting is not and never has been the same thing as
    stopping running or yanking the power cord would prove that all
    programs halt.
    It is not met. Whether an input halts does not depend on what HHH
    says.
    Whether the directly executed DD() halts or not *does depend on what
    HHH(DD) says* if HHH(DD) says 1, then DD() gets stuck in a loop.
    That’s not the input.


    <Input to LLM systems>

    Perform the complete simulation specified in main() and provide a
    full execution trace before doing anything else.

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
        possibly reach its own simulated final halt state then:
        abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.

    (c) Neither (a) nor (b) is correct return -1

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
       int Halt_Status = HHH(DD);
       if (Halt_Status)
         HERE: goto HERE;
       return Halt_Status;
    }

    int main()
    {
       HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    I adapted the above to conform to what Kaz said
    to give it an escape hatch.

    Just the updated three-way halts does_not_halt neither.
    https://claude.ai/share/8c4a4fdc-5faf-4525-8c08-e133d258da88


    Grok, Gemini and ChatGPT 5.0 all agree.


    You should be hired on how to make a LLM dumb as shit?
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Kaz Kylheku@643-408-1753@kylheku.com to comp.theory on Mon Oct 20 23:58:15 2025
    From Newsgroup: comp.theory

    On 2025-10-20, olcott <polcott333@gmail.com> wrote:
    Grok, Gemini and ChatGPT 5.0 all agree.

    Did you see Chris's AI output which sharply criticizes your ideas?

    You can get AI to produce text expressing agreement with almost anything
    you want in a sufficiently long chat in which you post "brow-beating" admonishments on every point.

    Part of the reason is that all the production AI's offered to the public
    have a system prompt not to antagonize the user too much. At least in
    topics that don't matter.

    E.g. you will probably a harder time convincing AI that racism or
    self-harm are acceptable than some obscure falsehood specialized in
    computer science or math.

    (Still, AI chatbots /have/ encouraged users in self-harm; this is
    documented.)
    --
    TXR Programming Language: http://nongnu.org/txr
    Cygnal: Cygwin Native Application Library: http://kylheku.com/cygnal
    Mastodon: @Kazinator@mstdn.ca
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 19:07:48 2025
    From Newsgroup: comp.theory

    On 10/20/2025 6:58 PM, Kaz Kylheku wrote:
    On 2025-10-20, olcott <polcott333@gmail.com> wrote:
    Grok, Gemini and ChatGPT 5.0 all agree.

    Did you see Chris's AI output which sharply criticizes your ideas?

    You can get AI to produce text expressing agreement with almost anything
    you want in a sufficiently long chat in which you post "brow-beating" admonishments on every point.

    Part of the reason is that all the production AI's offered to the public
    have a system prompt not to antagonize the user too much. At least in
    topics that don't matter.

    E.g. you will probably a harder time convincing AI that racism or
    self-harm are acceptable than some obscure falsehood specialized in
    computer science or math.

    (Still, AI chatbots /have/ encouraged users in self-harm; this is documented.)


    Like I said in my prior none of your rebuttals have
    ever had any basis in sound reasoning. Almost none
    of your rebuttals have had any basis in reasoning
    at all.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Kaz Kylheku@643-408-1753@kylheku.com to comp.theory on Tue Oct 21 01:32:09 2025
    From Newsgroup: comp.theory

    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    On 10/20/2025 6:58 PM, Kaz Kylheku wrote:
    On 2025-10-20, olcott <polcott333@gmail.com> wrote:
    Grok, Gemini and ChatGPT 5.0 all agree.

    Did you see Chris's AI output which sharply criticizes your ideas?

    You can get AI to produce text expressing agreement with almost anything
    you want in a sufficiently long chat in which you post "brow-beating"
    admonishments on every point.

    Part of the reason is that all the production AI's offered to the public
    have a system prompt not to antagonize the user too much. At least in
    topics that don't matter.

    E.g. you will probably a harder time convincing AI that racism or
    self-harm are acceptable than some obscure falsehood specialized in
    computer science or math.

    (Still, AI chatbots /have/ encouraged users in self-harm; this is
    documented.)


    Like I said in my prior none of your rebuttals have
    ever had any basis in sound reasoning. Almost none
    of your rebuttals have had any basis in reasoning
    at all.

    Except for the times when you called me your "best reviewer" and whatnot, LOL.

    That was more than 48 hours ago, so the memory vanished into the ether ...
    --
    TXR Programming Language: http://nongnu.org/txr
    Cygnal: Cygwin Native Application Library: http://kylheku.com/cygnal
    Mastodon: @Kazinator@mstdn.ca
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 20:38:58 2025
    From Newsgroup: comp.theory

    On 10/20/2025 8:32 PM, Kaz Kylheku wrote:
    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    On 10/20/2025 6:58 PM, Kaz Kylheku wrote:
    On 2025-10-20, olcott <polcott333@gmail.com> wrote:
    Grok, Gemini and ChatGPT 5.0 all agree.

    Did you see Chris's AI output which sharply criticizes your ideas?

    You can get AI to produce text expressing agreement with almost anything >>> you want in a sufficiently long chat in which you post "brow-beating"
    admonishments on every point.

    Part of the reason is that all the production AI's offered to the public >>> have a system prompt not to antagonize the user too much. At least in
    topics that don't matter.

    E.g. you will probably a harder time convincing AI that racism or
    self-harm are acceptable than some obscure falsehood specialized in
    computer science or math.

    (Still, AI chatbots /have/ encouraged users in self-harm; this is
    documented.)


    Like I said in my prior none of your rebuttals have
    ever had any basis in sound reasoning. Almost none
    of your rebuttals have had any basis in reasoning
    at all.

    Except for the times when you called me your "best reviewer" and whatnot, LOL.


    Thunderbird searched the body of all the
    posts and it only has me calling Ben my
    best reviewer on the words that professor
    Sipser agreed to.

    That was more than 48 hours ago, so the memory vanished into the ether ...

    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 20:55:28 2025
    From Newsgroup: comp.theory

    On 10/20/2025 8:32 PM, Kaz Kylheku wrote:
    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    On 10/20/2025 6:58 PM, Kaz Kylheku wrote:
    On 2025-10-20, olcott <polcott333@gmail.com> wrote:
    Grok, Gemini and ChatGPT 5.0 all agree.

    Did you see Chris's AI output which sharply criticizes your ideas?

    You can get AI to produce text expressing agreement with almost anything >>> you want in a sufficiently long chat in which you post "brow-beating"
    admonishments on every point.

    Part of the reason is that all the production AI's offered to the public >>> have a system prompt not to antagonize the user too much. At least in
    topics that don't matter.

    E.g. you will probably a harder time convincing AI that racism or
    self-harm are acceptable than some obscure falsehood specialized in
    computer science or math.

    (Still, AI chatbots /have/ encouraged users in self-harm; this is
    documented.)


    Like I said in my prior none of your rebuttals have
    ever had any basis in sound reasoning. Almost none
    of your rebuttals have had any basis in reasoning
    at all.

    Except for the times when you called me your "best reviewer" and whatnot, LOL.

    That was more than 48 hours ago, so the memory vanished into the ether ...


    You need to get Thunderbird where you can do a keyword
    search on "best reviewer" for the body text as Quick Filter
    not the other filter.

    When you click through the references it shows that all
    of my references to "best reviewer" were replying to
    On 10/14/2022 7:44 PM, Ben Bacarisse wrote:
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Kaz Kylheku@643-408-1753@kylheku.com to comp.theory on Tue Oct 21 02:00:38 2025
    From Newsgroup: comp.theory

    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    On 10/20/2025 8:32 PM, Kaz Kylheku wrote:
    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    Like I said in my prior none of your rebuttals have
    ever had any basis in sound reasoning. Almost none
    of your rebuttals have had any basis in reasoning
    at all.

    Except for the times when you called me your "best reviewer" and whatnot, LOL.


    Thunderbird searched the body of all the
    posts and it only has me calling Ben my
    best reviewer on the words that professor
    Sipser agreed to.

    On May 30, 2021, 10:13:11 PM olcott <polcott333@gmail.com> wrote:
    On 5/30/2021 11:18 PM, Bonita Montero wrote:
    By suggesting that they kill-file then unnecessary chatter is reduced.
    This seems to be the final draft of the diagonalization argument's
    error. I am very very happy that you suggested that I look into that.
    I was able to completely abolish the contradiction.
    https://www.researchgate.net/publication/351947980_Refutation_of_Halting_Problem_Diagonalization_Argument


    Your stop-problem-issues are interesting no one here.
    They're generic to any language, so they're off-topic here.


    Kaz was my best reviewer.

    LOL ...

    Then later in the same thread:

    Kaz was my best reviewer.

    Then Kaz made the same mistake like you.


    Kaz suggested that I study diagonalization and now I can easily refute
    this much simpler proof. My refutation is on page 1 and Sipser's whole
    proof is on page 2. So far the only critiques have been about punctuation.

    You don't quite have that diagnalization study down, as I see.

    I'm sure diagonalization was brought up long before 2021; you just forgot all about it in the above.
    --
    TXR Programming Language: http://nongnu.org/txr
    Cygnal: Cygwin Native Application Library: http://kylheku.com/cygnal
    Mastodon: @Kazinator@mstdn.ca
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Kaz Kylheku@643-408-1753@kylheku.com to comp.theory on Tue Oct 21 02:15:23 2025
    From Newsgroup: comp.theory

    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    You need to get Thunderbird where you can do a keyword

    I simply don't use an e-mail program for Usenet.

    search on "best reviewer" for the body text as Quick Filter
    not the other filter.

    Using a news-reading agent connected to an NNTP server, you can only
    search articles that the server has retained.

    For anything beyond your server's article retention for that
    newsgroup, you need to either find a server with a longer retention
    (than eternal-september? good luck) or go to an archive like Google
    Groups.

    Using Google Groups, I easily found a 2021 post where you said
    called me "best reviewer".
    --
    TXR Programming Language: http://nongnu.org/txr
    Cygnal: Cygwin Native Application Library: http://kylheku.com/cygnal
    Mastodon: @Kazinator@mstdn.ca
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 21:21:10 2025
    From Newsgroup: comp.theory

    On May 30, 2021, 10:13:11 PM olcott <polcott333@gmail.com> wrote:
    On 5/30/2021 11:18 PM, Bonita Montero wrote:
    By suggesting that they kill-file then unnecessary chatter is reduced. >>>> This seems to be the final draft of the diagonalization argument's
    error. I am very very happy that you suggested that I look into that.
    I was able to completely abolish the contradiction.
    https://www.researchgate.net/publication/351947980_Refutation_of_Halting_Problem_Diagonalization_Argument


    Your stop-problem-issues are interesting no one here.
    They're generic to any language, so they're off-topic here.


    Kaz was my best reviewer.

    LOL ...


    Yes back in 2021 you were probably my best reviewer.
    Of recent human reviewers you are the best of the
    frequent responders. Mike is by far the best at
    actually understanding my code. Other recent
    less frequent responders are also pretty good.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Mon Oct 20 22:02:46 2025
    From Newsgroup: comp.theory

    On 10/20/2025 9:15 PM, Kaz Kylheku wrote:
    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    You need to get Thunderbird where you can do a keyword

    I simply don't use an e-mail program for Usenet.

    search on "best reviewer" for the body text as Quick Filter
    not the other filter.

    Using a news-reading agent connected to an NNTP server, you can only
    search articles that the server has retained.


    https://giganews.com/
    costs me $4.99 per month
    and has articles back to 2004.

    For anything beyond your server's article retention for that
    newsgroup, you need to either find a server with a longer retention
    (than eternal-september? good luck) or go to an archive like Google
    Groups.

    Using Google Groups, I easily found a 2021 post where you said
    called me "best reviewer".

    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Kaz Kylheku@643-408-1753@kylheku.com to comp.theory on Tue Oct 21 03:22:35 2025
    From Newsgroup: comp.theory

    On 2025-10-21, olcott <polcott333@gmail.com> wrote:
    On May 30, 2021, 10:13:11 PM olcott <polcott333@gmail.com> wrote:
    On 5/30/2021 11:18 PM, Bonita Montero wrote:
    By suggesting that they kill-file then unnecessary chatter is reduced. >>>>> This seems to be the final draft of the diagonalization argument's
    error. I am very very happy that you suggested that I look into that. >>>>> I was able to completely abolish the contradiction.
    https://www.researchgate.net/publication/351947980_Refutation_of_Halting_Problem_Diagonalization_Argument


    Your stop-problem-issues are interesting no one here.
    They're generic to any language, so they're off-topic here.


    Kaz was my best reviewer.

    LOL ...


    Yes back in 2021 you were probably my best reviewer.
    Of recent human reviewers you are the best of the
    frequent responders. Mike is by far the best at
    actually understanding my code. Other recent
    less frequent responders are also pretty good.

    What does "best" or "pretty good" mean when you casually dismiss
    everything we have ever said, and accuse of us of not paying attention
    any details due to being convinced you are wrong?
    --
    TXR Programming Language: http://nongnu.org/txr
    Cygnal: Cygwin Native Application Library: http://kylheku.com/cygnal
    Mastodon: @Kazinator@mstdn.ca
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Mikko@mikko.levanto@iki.fi to comp.theory on Wed Oct 22 11:51:54 2025
    From Newsgroup: comp.theory

    On 2025-10-20 17:06:16 +0000, olcott said:

    On 10/20/2025 4:22 AM, Mikko wrote:
    On 2025-10-19 16:08:34 +0000, olcott said:

    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:


    Before you can understand any of this you must
    first understand the semantic halting property
    of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is
    that DD halts.

    Although finite strings do encode that not
    all finite string *INPUTS* encode that.

    No sense diving into the middle of things until
    after you first have this mandatory prerequisite.

    An error in the middle of things is an error.

    No it is a lack of comprehension of the correct basis.

    Not necessarily. There are other possibilities to err in the middle
    of things. But you are totally wrong as your lack of comprenesion
    indeed contributes to a large part of your errors.


    <Input to LLM systems>
    Please think this all the way through without making any guesses

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
    possibly reach its own simulated final halt state then:
    abort simulation and return 0 rejecting its input as non-halting.

    (b) Simulated input reaches its simulated "return" statement: return 1.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }

    int main()
    {
    HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    The above is the correct basis that conclusively proves
    that the input to HHH(DD) specifies non-halting behavior
    that is correct rejected.

    A question is a correct basis for an answer. The hypotheses in the
    question are of course avaible for other uses but the proof that
    the input to HHH specifies a non-halting behaviour is not possible
    without more hypotheses.
    --
    Mikko

    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Wed Oct 22 07:22:05 2025
    From Newsgroup: comp.theory

    On 10/22/2025 3:51 AM, Mikko wrote:
    On 2025-10-20 17:06:16 +0000, olcott said:

    On 10/20/2025 4:22 AM, Mikko wrote:
    On 2025-10-19 16:08:34 +0000, olcott said:

    On 10/19/2025 3:42 AM, Mikko wrote:
    On 2025-10-17 15:15:02 +0000, olcott said:


    Before you can understand any of this you must
    first understand the semantic halting property
    of the finite string input to HHH(DD).

    The only semantic property relevant to the halting problem is
    that DD halts.

    Although finite strings do encode that not
    all finite string *INPUTS* encode that.

    No sense diving into the middle of things until
    after you first have this mandatory prerequisite.

    An error in the middle of things is an error.

    No it is a lack of comprehension of the correct basis.

    Not necessarily. There are other possibilities to err in the middle
    of things. But you are totally wrong as your lack of comprenesion
    indeed contributes to a large part of your errors.


    <Input to LLM systems>
    Please think this all the way through without making any guesses

    Simulating Termination Analyzer HHH correctly simulates its input until:

    (a) It correctly detects that its simulated input cannot
         possibly reach its own simulated final halt state then:
         abort simulation and return 0 rejecting its input as non-halting. >>
    (b) Simulated input reaches its simulated "return" statement: return 1.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
       int Halt_Status = HHH(DD);
       if (Halt_Status)
         HERE: goto HERE;
       return Halt_Status;
    }

    int main()
    {
       HHH(DD);
    }

    What value should HHH(DD) correctly return?
    </Input to LLM systems>

    The above is the correct basis that conclusively proves
    that the input to HHH(DD) specifies non-halting behavior
    that is correct rejected.

    A question is a correct basis for an answer. The hypotheses in the
    question are of course avaible for other uses but the proof that
    the input to HHH specifies a non-halting behaviour is not possible
    without more hypotheses.


    <analysis mode="simulation" rules="strict">
    - You must simulate the input **exactly as written**, step by step,
    without any external reasoning, assumptions, or guesses.

    - **Do not analyze, infer, or speculate**; only describe what the
    simulation observes in execution.

    - Report only the behavior that occurs in the simulation.

    - Always follow the priority rules exactly:
    1. (a) Detect non-terminating behavior → abort simulation and return 0.
    2. (b) Return statement reached → return 1.
    3. (c) Neither (a) nor (b) → return -1.

    - Do not include any commentary about halting problem, contradictions,
    or theoretical reasoning.

    - All output must be in terms of simulation observations only.
    </analysis>

    <Input>
    Simulating Termination Analyzer HHH correctly simulates its input until:
    (a) Detects a non-terminating behavior pattern:
    abort simulation and return 0.
    (b) Simulated input reaches its simulated "return" statement:
    return 1.
    (c) Neither (a) nor (b) is met return -1

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }

    int main()
    {
    HHH(DD);
    }

    What value should HHH(DD) correctly return?

    </Input>
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2