Hi,
Functional requirement:
?- Y = g(_,_), X = f(Y,C,D,Y), term_singletons(X, L),
L == [C,D].
?- Y = g(A,X,B), X = f(Y,C,D), term_singletons(X, L),
L == [A,B,C,D].
Non-Functional requirement:
?- member(N,[5,10,15]), time(singletons(N)), fail; true.
% Zeit 1 ms, GC 0 ms, Lips 4046000, Uhr 11.08.2025 01:36
% Zeit 3 ms, GC 0 ms, Lips 1352000, Uhr 11.08.2025 01:36
% Zeit 3 ms, GC 0 ms, Lips 1355333, Uhr 11.08.2025 01:36
true.
Can your Prolog system do that?
P.S.: Benchmark was:
singletons(N) :-
hydra2(N,Y),
between(1,1000,_), term_singletons(Y,_), fail; true.
hydra2(0, _) :- !.
hydra2(N, s(X,X)) :-
M is N-1,
hydra2(M, X).
Bye
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