On 7/3/2026 10:37 PM, olcott wrote:
On 7/3/2026 9:19 PM, dbush wrote:
On 7/3/2026 10:05 PM, olcott wrote:
On 7/3/2026 8:58 PM, dbush wrote:
On 7/3/2026 9:52 PM, olcott wrote:
On 7/3/2026 5:51 PM, André G. Isaak wrote:The mathematical halting function:
On 2026-07-03 16:37, olcott wrote:
On 7/3/2026 1:47 PM, André G. Isaak wrote:
On 2026-07-03 12:36, olcott wrote:
On 7/3/2026 1:18 PM, dbush wrote:
If an algorithm takes an input and produces an output, that >>>>>>>>>>> is by definition a mapping.That only proves that the definition is incoherent.
The coherent way that it actually works is that
inputs are transformed into outputs by applying
finite string transformation rules to inputs to
derive outputs.
Apparently you don't understand the difference between a
mapping and an algorithm. They are two different things.
André
A function that ignores its input and only returns 0
is not any sort of halt function.
He was defining 'mapping', not 'halt function'.
André
A actual halt function must compute
When you actually implement this concretely
We find that it is not possible, as Linz and others have proved.
Impossible requirements are incorrect requirements.
Nope. Requirements are requirements for a reason. If they can't be satisfied, then that's just the way it is.
I would like to have a single algorithm that can tell me whether any arbitrary algorithm with a given input will halt when executed directly,
but unfortunately no such algorithm exists.
On 7/3/2026 9:43 PM, dbush wrote:
On 7/3/2026 10:37 PM, olcott wrote:
On 7/3/2026 9:19 PM, dbush wrote:
On 7/3/2026 10:05 PM, olcott wrote:
On 7/3/2026 8:58 PM, dbush wrote:
On 7/3/2026 9:52 PM, olcott wrote:
On 7/3/2026 5:51 PM, André G. Isaak wrote:The mathematical halting function:
On 2026-07-03 16:37, olcott wrote:
On 7/3/2026 1:47 PM, André G. Isaak wrote:
On 2026-07-03 12:36, olcott wrote:
On 7/3/2026 1:18 PM, dbush wrote:
If an algorithm takes an input and produces an output, that >>>>>>>>>>>> is by definition a mapping.That only proves that the definition is incoherent.
The coherent way that it actually works is that
inputs are transformed into outputs by applying
finite string transformation rules to inputs to
derive outputs.
Apparently you don't understand the difference between a
mapping and an algorithm. They are two different things.
André
A function that ignores its input and only returns 0
is not any sort of halt function.
He was defining 'mapping', not 'halt function'.
André
A actual halt function must compute
When you actually implement this concretely
We find that it is not possible, as Linz and others have proved.
Impossible requirements are incorrect requirements.
Nope. Requirements are requirements for a reason. If they can't be
satisfied, then that's just the way it is.
The halting problem requires a decider that correctly reports the halt status of an input that does the opposite of whatever it reports.
On 7/3/2026 9:43 PM, dbush wrote:
On 7/3/2026 10:37 PM, olcott wrote:
On 7/3/2026 9:19 PM, dbush wrote:
On 7/3/2026 10:05 PM, olcott wrote:
On 7/3/2026 8:58 PM, dbush wrote:
On 7/3/2026 9:52 PM, olcott wrote:
On 7/3/2026 5:51 PM, André G. Isaak wrote:The mathematical halting function:
On 2026-07-03 16:37, olcott wrote:
On 7/3/2026 1:47 PM, André G. Isaak wrote:
On 2026-07-03 12:36, olcott wrote:
On 7/3/2026 1:18 PM, dbush wrote:
If an algorithm takes an input and produces an output, that >>>>>>>>>>>> is by definition a mapping.That only proves that the definition is incoherent.
The coherent way that it actually works is that
inputs are transformed into outputs by applying
finite string transformation rules to inputs to
derive outputs.
Apparently you don't understand the difference between a
mapping and an algorithm. They are two different things.
André
A function that ignores its input and only returns 0
is not any sort of halt function.
He was defining 'mapping', not 'halt function'.
André
A actual halt function must compute
When you actually implement this concretely
We find that it is not possible, as Linz and others have proved.
Impossible requirements are incorrect requirements.
Nope. Requirements are requirements for a reason. If they can't be
satisfied, then that's just the way it is.
The halting problem requires a decider that correctly reports the halt status of an input that does the opposite of whatever it reports. The meaning of these words prove that is logically impossible.
I would like to have a single algorithm that can tell me whether any
arbitrary algorithm with a given input will halt when executed
directly, but unfortunately no such algorithm exists.
typedef int (*ptr)();
int HHH(ptr P);
01 int DD()
02 {
03 int Halt_Status = HHH(DD);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
08
09 void main()
10 {
11 DD();
12 HHH(DD);
13 }
HHH is not accountable to report on the
behavior of its caller on line 11.
On 04/07/2026 20:16, olcott wrote:
On 7/4/2026 3:58 AM, Mikko wrote:
On 04/07/2026 06:11, olcott wrote:
On 7/3/2026 9:43 PM, dbush wrote:
On 7/3/2026 10:37 PM, olcott wrote:
On 7/3/2026 9:19 PM, dbush wrote:
On 7/3/2026 10:05 PM, olcott wrote:
On 7/3/2026 8:58 PM, dbush wrote:
On 7/3/2026 9:52 PM, olcott wrote:
On 7/3/2026 5:51 PM, André G. Isaak wrote:The mathematical halting function:
On 2026-07-03 16:37, olcott wrote:
On 7/3/2026 1:47 PM, André G. Isaak wrote:
On 2026-07-03 12:36, olcott wrote:
On 7/3/2026 1:18 PM, dbush wrote:
If an algorithm takes an input and produces an output, >>>>>>>>>>>>>>> that is by definition a mapping.That only proves that the definition is incoherent. >>>>>>>>>>>>>> The coherent way that it actually works is that
inputs are transformed into outputs by applying
finite string transformation rules to inputs to
derive outputs.
Apparently you don't understand the difference between a >>>>>>>>>>>>> mapping and an algorithm. They are two different things. >>>>>>>>>>>>>
André
A function that ignores its input and only returns 0
is not any sort of halt function.
He was defining 'mapping', not 'halt function'.
André
A actual halt function must compute
When you actually implement this concretely
We find that it is not possible, as Linz and others have proved. >>>>>>>
Impossible requirements are incorrect requirements.
Nope. Requirements are requirements for a reason. If they can't >>>>> be satisfied, then that's just the way it is.
The halting problem requires a decider that correctly reports the
halt status of an input that does the opposite of whatever it
reports. The meaning of these words prove that is logically impossible. >>>>
I would like to have a single algorithm that can tell me whether
any arbitrary algorithm with a given input will halt when executed
directly, but unfortunately no such algorithm exists.
typedef int (*ptr)();
int HHH(ptr P);
01 int DD()
02 {
03 int Halt_Status = HHH(DD);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
08
09 void main()
10 {
11 DD();
12 HHH(DD);
13 }
HHH is not accountable to report on the
behavior of its caller on line 11.
It is if HHH reagards itself as a part of the input.
There is no regarding to it
HHH is not accountable to report on the
behavior of its caller on line 11.
Yes, there is. If HHH interpretes the call to HHH as a call
to itself then it must regard itself as a part of the input.
Otherwise it must interprete HHH as a call to some function
other than itself, so it must regard itself as not a part of
the input. EIther way, it must report correcltly about the
behaviour as obsservable in an execution of the computation
specified by the input.
Of course this is irrelevant to the Turing machine halting problem.
A Turing machine never calls another Turing machine.
On 7/6/2026 3:07 AM, Mikko wrote:
On 04/07/2026 20:16, olcott wrote:
On 7/4/2026 3:58 AM, Mikko wrote:
On 04/07/2026 06:11, olcott wrote:
On 7/3/2026 9:43 PM, dbush wrote:
On 7/3/2026 10:37 PM, olcott wrote:
On 7/3/2026 9:19 PM, dbush wrote:
On 7/3/2026 10:05 PM, olcott wrote:
On 7/3/2026 8:58 PM, dbush wrote:
On 7/3/2026 9:52 PM, olcott wrote:
On 7/3/2026 5:51 PM, André G. Isaak wrote:The mathematical halting function:
On 2026-07-03 16:37, olcott wrote:
On 7/3/2026 1:47 PM, André G. Isaak wrote:
On 2026-07-03 12:36, olcott wrote:
On 7/3/2026 1:18 PM, dbush wrote:
If an algorithm takes an input and produces an output, >>>>>>>>>>>>>>>> that is by definition a mapping.That only proves that the definition is incoherent. >>>>>>>>>>>>>>> The coherent way that it actually works is that
inputs are transformed into outputs by applying
finite string transformation rules to inputs to
derive outputs.
Apparently you don't understand the difference between a >>>>>>>>>>>>>> mapping and an algorithm. They are two different things. >>>>>>>>>>>>>>
André
A function that ignores its input and only returns 0 >>>>>>>>>>>>> is not any sort of halt function.
He was defining 'mapping', not 'halt function'.
André
A actual halt function must compute
When you actually implement this concretely
We find that it is not possible, as Linz and others have proved. >>>>>>>>
Impossible requirements are incorrect requirements.
Nope. Requirements are requirements for a reason. If they can't >>>>>> be satisfied, then that's just the way it is.
The halting problem requires a decider that correctly reports the
halt status of an input that does the opposite of whatever it
reports. The meaning of these words prove that is logically
impossible.
I would like to have a single algorithm that can tell me whether
any arbitrary algorithm with a given input will halt when executed >>>>>> directly, but unfortunately no such algorithm exists.
typedef int (*ptr)();
int HHH(ptr P);
01 int DD()
02 {
03 int Halt_Status = HHH(DD);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
08
09 void main()
10 {
11 DD();
12 HHH(DD);
13 }
HHH is not accountable to report on the
behavior of its caller on line 11.
It is if HHH reagards itself as a part of the input.
There is no regarding to it
HHH is not accountable to report on the
behavior of its caller on line 11.
Yes, there is. If HHH interpretes the call to HHH as a call
You did not bother to pay attention to the line number 11.
The HP stupidly assumes that a halt function must report
on the behavior its caller. HHH has no access to its caller.
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