• Re: Simplified Halting Problem Proof Rebuttal

    From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 07:36:10 2023
    From Newsgroup: comp.ai.philosophy

    On 10/15/23 11:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that
    Turing's halting problem proof is erroneous. I have simplified it for >>>>>> people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self-
    contradictory expressions are not true. “This sentence is not
    true.” is
    not true and that does not make it true. As a corollary to this self- >>>>>> contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked]
    changes
    the meaning of this question, this context cannot be correctly
    ignored.
    When Jack's question is posed to Jack it has no correct answer.

    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no}
    are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer
    program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem instance* >>>>>> When decision problem instance decider/input has no correct Boolean >>>>>> value that the decider can return then this is stipulated to be an >>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever
    decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not mean that >>>>>> an algorithm is too weak to find the steps required to reach a
    correct
    Boolean return value.

    It actually means that no correct Boolean return value exists for >>>>>> this
    decision problem instance.

    Because people subconsciously implicitly refer to the original
    meaning
    of undecidable [can't make up one's mind] they misconstrue a
    decider/input pair with no correct Boolean return value from the
    decider
    as the fault of the decider and thus not the fault of the input.



    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an incorrect >>>> question in that both answers from the solution set of {yes, no} are
    the
    wrong answer.

    Likewise no computer program H can say what another computer program
    D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory questions* >>>> when the full context of *who is asked* is understood to be a mandatory >>>> aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Yes, an no element of that set meets the requirement of a Halt Decider,
    and every input to all the sets has a definite answer to the ACTUAL
    question (does the input represent a machine that will halt on its given input), so your argument fails.

    All your question done is prove that fact, so it doesn't REFUTE the
    Halting Theorem claim that no correct Halt Deciders can exist, but
    PROVES it.

    The fact that you seem to think that a statement proving a Theorem,
    Refutes it, shows you are stupid.

    To think you can replace a question with a different one that has a
    (subtly) different meaning shows your think logical fallacies are good
    logic, again proving your stupidity.

    The fact that you continue to not quote the statement you are replying
    to shows that you know your arguments are incorrect, and they can't
    stand being put up against the rebuttals give, proving you are just a deceitful liar.

    In short, you are admitting to being a source of the disinformation that
    you claim to be fighting, making you a Hypocrite.

    Face it, you have ruined your life and are going to spend eternity
    facing your errors.


    Also note just because your set of H is infinite, doesn't mean it
    contains ALL of the possible Halt Deciders, there are infinite sets that
    are proper subsets of other infinite sets, and due to the (perhaps
    confusing to small minds like yours) fact that some mathematics works differently on infinite number, your logic just fails.
    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From olcott@polcott2@gmail.com to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 09:18:56 2023
    From Newsgroup: comp.ai.philosophy

    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that
    Turing's halting problem proof is erroneous. I have simplified it for >>>>>> people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self-
    contradictory expressions are not true. “This sentence is not
    true.” is
    not true and that does not make it true. As a corollary to this self- >>>>>> contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked]
    changes
    the meaning of this question, this context cannot be correctly
    ignored.
    When Jack's question is posed to Jack it has no correct answer.

    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no}
    are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer
    program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem instance* >>>>>> When decision problem instance decider/input has no correct Boolean >>>>>> value that the decider can return then this is stipulated to be an >>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever
    decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not mean that >>>>>> an algorithm is too weak to find the steps required to reach a
    correct
    Boolean return value.

    It actually means that no correct Boolean return value exists for >>>>>> this
    decision problem instance.

    Because people subconsciously implicitly refer to the original
    meaning
    of undecidable [can't make up one's mind] they misconstrue a
    decider/input pair with no correct Boolean return value from the
    decider
    as the fault of the decider and thus not the fault of the input.



    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an incorrect >>>> question in that both answers from the solution set of {yes, no} are
    the
    wrong answer.

    Likewise no computer program H can say what another computer program
    D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory questions* >>>> when the full context of *who is asked* is understood to be a mandatory >>>> aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input D
    where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.

    Neither return value of true/false is correct for each decider/input
    pair because each element <is> a self-contradictory question.

    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    where gullible fools can honestly believe that there are HP
    instances that have not been accounted for.

    People stuck in rebuttal mode may try to claim that an infinite set
    of program/input pairs have zero elements that are programs, yet this
    is very obviously quite foolish.
    --
    Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer

    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 18:49:33 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/23 10:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>> Turing's halting problem proof is erroneous. I have simplified it >>>>>>> for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self-
    contradictory expressions are not true. “This sentence is not >>>>>>> true.” is
    not true and that does not make it true. As a corollary to this >>>>>>> self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked] >>>>>>> changes
    the meaning of this question, this context cannot be correctly
    ignored.
    When Jack's question is posed to Jack it has no correct answer.

    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>> are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer
    program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem
    instance*
    When decision problem instance decider/input has no correct Boolean >>>>>>> value that the decider can return then this is stipulated to be an >>>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not mean >>>>>>> that
    an algorithm is too weak to find the steps required to reach a
    correct
    Boolean return value.

    It actually means that no correct Boolean return value exists for >>>>>>> this
    decision problem instance.

    Because people subconsciously implicitly refer to the original
    meaning
    of undecidable [can't make up one's mind] they misconstrue a
    decider/input pair with no correct Boolean return value from the >>>>>>> decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no}
    are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory questions* >>>>> when the full context of *who is asked* is understood to be a
    mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input D
    where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.

    Right.

    You have an infinite number of deciders, each being given a different
    input, so you have an infinite number of instances of the Halting Problem.

    You are just showing that NONE of your decider give the right answer,
    which supports the Halting Theorem

    Neither return value of true/false is correct for each decider/input
    pair because each element <is> a self-contradictory question.


    Wrong, for EVERY input, there is a correct answer, it just isn't the one
    that its H gives. Thus, NONE of the questions are contradictory.

    So, the fact that 1 + 1 = 2, but 2 + 2 = 4 means that addition is contraditory? That is two different problems with different answers?

    You are just proving your stupidity.

    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    where gullible fools can honestly believe that there are HP
    instances that have not been accounted for.


    Nope. Each element has a DIFFERENT input, so it is a DIFFERENT question.

    People stuck in rebuttal mode may try to claim that an infinite set
    of program/input pairs have zero elements that are programs, yet this
    is very obviously quite foolish.


    Maybe if you try to actually answer the rebuttals you would look so stupid.
    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From olcott@polcott2@gmail.com to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 18:38:07 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>> Turing's halting problem proof is erroneous. I have simplified it >>>>>>> for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self-
    contradictory expressions are not true. “This sentence is not >>>>>>> true.” is
    not true and that does not make it true. As a corollary to this >>>>>>> self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked] >>>>>>> changes
    the meaning of this question, this context cannot be correctly
    ignored.
    When Jack's question is posed to Jack it has no correct answer.

    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>> are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer
    program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem
    instance*
    When decision problem instance decider/input has no correct Boolean >>>>>>> value that the decider can return then this is stipulated to be an >>>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not mean >>>>>>> that
    an algorithm is too weak to find the steps required to reach a
    correct
    Boolean return value.

    It actually means that no correct Boolean return value exists for >>>>>>> this
    decision problem instance.

    Because people subconsciously implicitly refer to the original
    meaning
    of undecidable [can't make up one's mind] they misconstrue a
    decider/input pair with no correct Boolean return value from the >>>>>>> decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no}
    are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory questions* >>>>> when the full context of *who is asked* is understood to be a
    mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input D
    where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.
    --
    Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer

    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 20:53:44 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/23 7:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>> Turing's halting problem proof is erroneous. I have simplified >>>>>>>> it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self-
    contradictory expressions are not true. “This sentence is not >>>>>>>> true.” is
    not true and that does not make it true. As a corollary to this >>>>>>>> self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked] >>>>>>>> changes
    the meaning of this question, this context cannot be correctly >>>>>>>> ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an >>>>>>>> incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>>> are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer
    program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem
    instance*
    When decision problem instance decider/input has no correct Boolean >>>>>>>> value that the decider can return then this is stipulated to be an >>>>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not mean >>>>>>>> that
    an algorithm is too weak to find the steps required to reach a >>>>>>>> correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the original >>>>>>>> meaning
    of undecidable [can't make up one's mind] they misconstrue a
    decider/input pair with no correct Boolean return value from the >>>>>>>> decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no}
    are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory
    questions*
    when the full context of *who is asked* is understood to be a
    mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input D
    where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    But that isn't the question, the question is, "does the machine
    represented by the input halt?"

    THAT question has an answer.

    Your whole arguement is based on LIES.


    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.



    Nope, same input, the same description of the same machine, so same
    question and same answer.

    WHy does it matter WHO you ask does 1+1=2 ?

    It is a fundamental fact that D(D) will Halt (since its copy of H(D,D)
    returns 0)

    You are just proving your are a lying stupid idiot that doesn't
    understand what he is talking about but who makes up lies to try and get
    his way.
    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From olcott@polcott2@gmail.com to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 21:04:33 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>> Turing's halting problem proof is erroneous. I have simplified >>>>>>>> it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self-
    contradictory expressions are not true. “This sentence is not >>>>>>>> true.” is
    not true and that does not make it true. As a corollary to this >>>>>>>> self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked] >>>>>>>> changes
    the meaning of this question, this context cannot be correctly >>>>>>>> ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an >>>>>>>> incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>>> are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer
    program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem
    instance*
    When decision problem instance decider/input has no correct Boolean >>>>>>>> value that the decider can return then this is stipulated to be an >>>>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not mean >>>>>>>> that
    an algorithm is too weak to find the steps required to reach a >>>>>>>> correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the original >>>>>>>> meaning
    of undecidable [can't make up one's mind] they misconstrue a
    decider/input pair with no correct Boolean return value from the >>>>>>>> decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no}
    are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory
    questions*
    when the full context of *who is asked* is understood to be a
    mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input D
    where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.
    --
    Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer

    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 22:20:45 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/23 10:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>>> Turing's halting problem proof is erroneous. I have simplified >>>>>>>>> it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>> contradictory expressions are not true. “This sentence is not >>>>>>>>> true.” is
    not true and that does not make it true. As a corollary to this >>>>>>>>> self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked] >>>>>>>>> changes
    the meaning of this question, this context cannot be correctly >>>>>>>>> ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>> Boolean
    value that the decider can return then this is stipulated to be an >>>>>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach a >>>>>>>>> correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the original >>>>>>>>> meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>> are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory
    questions*
    when the full context of *who is asked* is understood to be a
    mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input
    D where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?

    Yes.

    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns

    Why is it "self-contradictory?" What "Self" did it contradict.

    D contradics H, not "itself".

    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    Nope.

    Since D(D) Halts ALWAYS the answer to, "does it halt?", is YES.

    ALWAYS.

    Even for H

    Remember, H was defined too, so H does what H always did. and is wrong.

    Nothong "Self-Contradictory", just WRONG, as are you.

    You are just proving yourself to be a lying idiot.


    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From olcott@polcott2@gmail.com to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 21:52:17 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/2023 9:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>>> Turing's halting problem proof is erroneous. I have simplified >>>>>>>>> it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>> contradictory expressions are not true. “This sentence is not >>>>>>>>> true.” is
    not true and that does not make it true. As a corollary to this >>>>>>>>> self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is asked] >>>>>>>>> changes
    the meaning of this question, this context cannot be correctly >>>>>>>>> ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>> Boolean
    value that the decider can return then this is stipulated to be an >>>>>>>>> incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach a >>>>>>>>> correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the original >>>>>>>>> meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question?
    and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an
    incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>> are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says.

    Both of the above two *are* essentially *self-contradictory
    questions*
    when the full context of *who is asked* is understood to be a
    mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input
    D where D does the opposite of of whatever Boolean value that H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.
    --
    Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer

    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 23:21:11 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/23 10:52 PM, olcott wrote:
    On 10/16/2023 9:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>>>> Turing's halting problem proof is erroneous. I have simplified >>>>>>>>>> it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>>> contradictory expressions are not true. “This sentence is not >>>>>>>>>> true.” is
    not true and that does not make it true. As a corollary to >>>>>>>>>> this self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is
    asked] changes
    the meaning of this question, this context cannot be correctly >>>>>>>>>> ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>>> Boolean
    value that the decider can return then this is stipulated to >>>>>>>>>> be an
    incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach a >>>>>>>>>> correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the original >>>>>>>>>> meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>> and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an >>>>>>>> incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>>> are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says. >>>>>>>>
    Both of the above two *are* essentially *self-contradictory
    questions*
    when the full context of *who is asked* is understood to be a >>>>>>>> mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input
    D where D does the opposite of of whatever Boolean value that H returns >>>> <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.


    So, you are just admitting that you don't understand your own argument
    or how programs work.

    You clearly don't understand what the *self* in self-contradictory
    means, maybe because your ego is just too big that you think you are everything.

    I guess that is why you think you are God. YOU AREN'T.

    H(D,D) Must ALLWAYS return the value it return, and H exists first,
    before D possibly can.

    You claim is basically the same as saying that Tic-Tac-Toe in an invalid
    game because there isn't a strategy to win it.

    And if there was, it would still be an invalid game, because it one
    player could always win, the other player can't also have a winning
    stratagy,

    The problem here is the Halt Desider Designer needs to move first and
    make the Halt Decider, then the challenger gets to make the input. And
    this game the second player wins.

    It isn't a "Self-Contradictory" problem, it is a problem that isn't computable, as are most problems.

    You just are too stupid to understand that.
    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Mon Oct 16 23:21:51 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/23 10:52 PM, olcott wrote:


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.


    H(D,D) can only return 1 value, becuase of how it is programed.

    It is a category error to talk about H returning anything other than
    what it is programmed to do.

    You clearly don't understand how programs work

    You don't even seem to know what "Self" means.

    You don't understand how logic works.

    You are just continuing to prove that you are nothing but a hypocritical
    lying idiot.

    You claim to want to fight disinformation, but you spread it yourself.

    You going down in history as a laughing stock.


    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From olcott@polcott2@gmail.com to sci.logic,comp.theory,comp.ai.philosophy on Tue Oct 17 23:10:20 2023
    From Newsgroup: comp.ai.philosophy

    On 10/16/2023 9:52 PM, olcott wrote:
    On 10/16/2023 9:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>>>> Turing's halting problem proof is erroneous. I have simplified >>>>>>>>>> it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>>> contradictory expressions are not true. “This sentence is not >>>>>>>>>> true.” is
    not true and that does not make it true. As a corollary to >>>>>>>>>> this self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is
    asked] changes
    the meaning of this question, this context cannot be correctly >>>>>>>>>> ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>>> Boolean
    value that the decider can return then this is stipulated to >>>>>>>>>> be an
    incorrect problem instance.

    We could also say that input D that does the opposite of whatever >>>>>>>>>> decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach a >>>>>>>>>> correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the original >>>>>>>>>> meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>> and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question?

    Jack's question when posed to Jack meets the definition of an >>>>>>>> incorrect
    question in that both answers from the solution set of {yes, no} >>>>>>>> are the
    wrong answer.

    Likewise no computer program H can say what another computer
    program D will do when D does the opposite of whatever H says. >>>>>>>>
    Both of the above two *are* essentially *self-contradictory
    questions*
    when the full context of *who is asked* is understood to be a >>>>>>>> mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and input
    D where D does the opposite of of whatever Boolean value that H returns >>>> <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.


    I told the computer science professor about
    the loophole you found in his work.
    --
    Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer

    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Wed Oct 18 07:04:30 2023
    From Newsgroup: comp.ai.philosophy

    On 10/18/23 12:10 AM, olcott wrote:
    On 10/16/2023 9:52 PM, olcott wrote:
    On 10/16/2023 9:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>>>>> Turing's halting problem proof is erroneous. I have
    simplified it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>>>> contradictory expressions are not true. “This sentence is not >>>>>>>>>>> true.” is
    not true and that does not make it true. As a corollary to >>>>>>>>>>> this self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is >>>>>>>>>>> asked] changes
    the meaning of this question, this context cannot be
    correctly ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>>>> Boolean
    value that the decider can return then this is stipulated to >>>>>>>>>>> be an
    incorrect problem instance.

    We could also say that input D that does the opposite of >>>>>>>>>>> whatever
    decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach >>>>>>>>>>> a correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the
    original meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>> and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>> no} are the
    wrong answer.

    Likewise no computer program H can say what another computer >>>>>>>>> program D will do when D does the opposite of whatever H says. >>>>>>>>>
    Both of the above two *are* essentially *self-contradictory >>>>>>>>> questions*
    when the full context of *who is asked* is understood to be a >>>>>>>>> mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and
    input D where D does the opposite of of whatever Boolean value that >>>>> H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.


    I told the computer science professor about
    the loophole you found in his work.


    Some how I don't believe you.

    A "Real" Conputer Science Professor wouldn't be trying to do this as
    they know better.

    And if the actually WERE going to try to do this, they would keep it
    totally secret until they submitted the paper to a Journal so they could
    get the credit.


    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From olcott@polcott2@gmail.com to sci.logic,comp.theory,comp.ai.philosophy on Wed Oct 18 09:48:39 2023
    From Newsgroup: comp.ai.philosophy

    On 10/17/2023 11:10 PM, olcott wrote:
    On 10/16/2023 9:52 PM, olcott wrote:
    On 10/16/2023 9:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show that >>>>>>>>>>> Turing's halting problem proof is erroneous. I have
    simplified it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>>>> contradictory expressions are not true. “This sentence is not >>>>>>>>>>> true.” is
    not true and that does not make it true. As a corollary to >>>>>>>>>>> this self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is >>>>>>>>>>> asked] changes
    the meaning of this question, this context cannot be
    correctly ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>>>> Boolean
    value that the decider can return then this is stipulated to >>>>>>>>>>> be an
    incorrect problem instance.

    We could also say that input D that does the opposite of >>>>>>>>>>> whatever
    decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach >>>>>>>>>>> a correct
    Boolean return value.

    It actually means that no correct Boolean return value exists >>>>>>>>>>> for this
    decision problem instance.

    Because people subconsciously implicitly refer to the
    original meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the input. >>>>>>>>>>>


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>> and that this is isomorphic to the HP decider/input pair
    is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>> no} are the
    wrong answer.

    Likewise no computer program H can say what another computer >>>>>>>>> program D will do when D does the opposite of whatever H says. >>>>>>>>>
    Both of the above two *are* essentially *self-contradictory >>>>>>>>> questions*
    when the full context of *who is asked* is understood to be a >>>>>>>>> mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H
    is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and
    input D where D does the opposite of of whatever Boolean value that >>>>> H returns
    <is> the infinite set of every halting problem decider/input pair.


    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.


    I told the computer science professor about
    the loophole you found in his work.


    Can Jack correctly answer “no” to this [yes/no] question?
    is a self-contradictory thus incorrect question when posed
    to Jack.

    Jack's question <is> precisely isomorphic to this question:
    "Does your input halt on its input?" when posed to H on input
    D such that D does the opposite of whatever Boolean value that
    H returns.

    That people have been well indoctrinated into the belief that
    the halting problem is correct any anyone saying otherwise is
    crazy has them ignore all of the facts and short-circuit to a
    counter-factual conclusion.
    --
    Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer

    --- Synchronet 3.20a-Linux NewsLink 1.114
  • From Richard Damon@richard@damon-family.org to sci.logic,comp.theory,comp.ai.philosophy on Wed Oct 18 11:25:26 2023
    From Newsgroup: comp.ai.philosophy

    On 10/18/23 10:48 AM, olcott wrote:
    On 10/17/2023 11:10 PM, olcott wrote:
    On 10/16/2023 9:52 PM, olcott wrote:
    On 10/16/2023 9:04 PM, olcott wrote:
    On 10/16/2023 6:38 PM, olcott wrote:
    On 10/16/2023 9:18 AM, olcott wrote:
    On 10/15/2023 10:49 PM, olcott wrote:
    On 10/15/2023 8:08 PM, olcott wrote:
    On 10/15/2023 7:26 PM, olcott wrote:
    On 10/15/2023 5:34 PM, olcott wrote:
    On 10/15/2023 2:07 PM, olcott wrote:
    On 10/15/2023 9:03 AM, olcott wrote:
    A PhD computer science professor came up with a way to show >>>>>>>>>>>> that
    Turing's halting problem proof is erroneous. I have
    simplified it for
    people that know nothing about computer programming.

    One thing that I found in my 20 year long quest is that self- >>>>>>>>>>>> contradictory expressions are not true. “This sentence is >>>>>>>>>>>> not true.” is
    not true and that does not make it true. As a corollary to >>>>>>>>>>>> this self-
    contradictory questions are incorrect.

    Linguistics understands that when the context of [who is >>>>>>>>>>>> asked] changes
    the meaning of this question, this context cannot be
    correctly ignored.
    When Jack's question is posed to Jack it has no correct answer. >>>>>>>>>>>>
    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>>>
    Jack's question when posed to Jack meets the definition of >>>>>>>>>>>> an incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>>>>> no} are the
    wrong answer.

    *Simplified Halting Problem Proof*
    Likewise no computer program H can say what another computer >>>>>>>>>>>> program D
    will do when D does the opposite of whatever H says.

    This meets the definition of an *incorrect decision problem >>>>>>>>>>>> instance*
    When decision problem instance decider/input has no correct >>>>>>>>>>>> Boolean
    value that the decider can return then this is stipulated to >>>>>>>>>>>> be an
    incorrect problem instance.

    We could also say that input D that does the opposite of >>>>>>>>>>>> whatever
    decider H returns is an invalid input for H.

    As everyone knows the technical term *undecidable* does not >>>>>>>>>>>> mean that
    an algorithm is too weak to find the steps required to reach >>>>>>>>>>>> a correct
    Boolean return value.

    It actually means that no correct Boolean return value >>>>>>>>>>>> exists for this
    decision problem instance.

    Because people subconsciously implicitly refer to the >>>>>>>>>>>> original meaning
    of undecidable [can't make up one's mind] they misconstrue a >>>>>>>>>>>> decider/input pair with no correct Boolean return value from >>>>>>>>>>>> the decider
    as the fault of the decider and thus not the fault of the >>>>>>>>>>>> input.



    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>> and that this is isomorphic to the HP decider/input pair >>>>>>>>>>> is the 100% complete essence of the whole proof.


    Can Jack correctly answer “no” to this [yes/no] question? >>>>>>>>>>
    Jack's question when posed to Jack meets the definition of an >>>>>>>>>> incorrect
    question in that both answers from the solution set of {yes, >>>>>>>>>> no} are the
    wrong answer.

    Likewise no computer program H can say what another computer >>>>>>>>>> program D will do when D does the opposite of whatever H says. >>>>>>>>>>
    Both of the above two *are* essentially *self-contradictory >>>>>>>>>> questions*
    when the full context of *who is asked* is understood to be a >>>>>>>>>> mandatory
    aspect of the meaning of these questions.


    There is a very simple principle here:
    Self-contradictory questions have no correct answer only
    because there is something wrong with the question.

    Both Jack's question posed to Jack and input D
    to program H that does the opposite of whatever
    H says are SELF-CONTRADICTORY QUESTIONS.


    This eliminates the https://en.wikipedia.org/wiki/Shell_game
    Of the infinite set of definitions for H where some D does
    the opposite of whatever Boolean value that this H returns
    none of them provides a Boolean value corresponding to the
    behavior of any D.

    Because I have stipulated infinite sets there cannot possibly
    be some other H or D that has not already been addressed.


    Each element of the infinite set of every possible encoding of H >>>>>>> is a program. I am sure that you already knew this.


    Each element of the set of every possible combination of H and
    input D where D does the opposite of of whatever Boolean value
    that H returns
    <is> the infinite set of every halting problem decider/input pair. >>>>>>

    "Wrong, for EVERY input, there is a correct answer"

    For every halting problem decider/input pair there
    is no correct Boolean value that can be returned
    by this decider because this input to this pair
    is a self-contradictory thus incorrect question
    for this decider.

    The some other decider can answer some other question
    is no rebuttal at all.

    An input D to a decider H1 having no pathological relationship
    to this decider is an entirely different question than this
    same input input to decider H that has been defined to do the
    opposite of whatever value that H returns.

    Does machine D halt on input D?
    Is a self-contradictory question for H when D is defined
    to do the opposite of whatever Boolean value that H returns
    and not a self-contradictory question for H1.

    That D contradicts H and does not contradict H1
    proves that these are two different questions.


    That H(D,D) cannot possibly return either Boolean
    value that corresponds to the direct execution of any
    D that is defined to do the opposite of whatever value
    that H returns proves that the decider/input pair is
    self-contradictory for this decider.

    When D does the opposite of whatever H says this
    <is> self-contradictory in the same way that
    "This sentence is not true." contradicts itself.


    I told the computer science professor about
    the loophole you found in his work.


    Can Jack correctly answer “no” to this [yes/no] question?
    is a self-contradictory thus incorrect question when posed
    to Jack.


    So, you continue to beat this dead Red Herring.

    Jack's question <is> precisely isomorphic to this question:
    "Does your input halt on its input?" when posed to H on input
    D such that D does the opposite of whatever Boolean value that
    H returns.


    Which is a Red Herring, because that isn't the halting problem question,
    an in fact, is a non-sense quesiton in this context.

    Since H is a DEFINED program, talking about it doing anything becides
    what it is actually programmed to do is meaningless.

    That is like saying "If 1+2 was 5, then ....", which is clearly non-sense.

    You CAN pull that sort of thing OUTSIDE the specific problem, and ask if
    it is possible to find some H that can get the right answer for the
    problem it creates, and there, the answer of No, you can not create an H
    that gives the right answer just becomes the proof of the Halting
    Theorem, that no such program exist. It doesn't show that any particular problem question was somehow invalid, because every Halting Problem
    Question (Does the machine described by this input Halt?) has a correct answer, it just isn't the answer that the decider that this input was
    built on gives.

    So, you are showing your stupidity by claiming that your have disprove
    the theorem when you have actually just proved it, which shows you just
    don't understand how logic (or truth) works.


    That people have been well indoctrinated into the belief that
    the halting problem is correct any anyone saying otherwise is
    crazy has them ignore all of the facts and short-circuit to a
    counter-factual conclusion.



    Nope, YOUR have gas-lit yourself into belieiving your own lies and thus
    can't face the facts. This is highlighted by the fact that you don't
    even TRY to answer the rebuttals. This just confirms that you know you
    don't have an answer to them are just using the fallacy of ignoring the
    truth. In other words, you are admitting defeat, but then continue to
    dig your own grave.

    You have proved to the world that you totally don't understand about how
    logic works, about what Truth means. You also seem to be telling it that Disinformation is an acceptable practice, since this is what you are
    using to proclaim your "vital" message, in other words, you are just sabotaging your own stated goals.

    IF you will TRY to even answer the errors pointed out, with ACTUAL
    FACTS, not just more of your puffed up statements, then maybe we can
    talk. Untill then, I will just smack down your repeated lies with strong words.
    --- Synchronet 3.20a-Linux NewsLink 1.114